4x^2+16x+9=-3

Solution for 4x^2+16x+9=-3 equation:

4x^2+16x+9=-3

We move all terms to the left:

4x^2+16x+9-(-3)=0

We add all the numbers together, and all the variables

4x^2+16x+12=0

a = 4; b = 16; c = +12;
Δ = b2-4ac
Δ = 162-4·4·12
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-8}{2*4}=\frac{-24}{8}
=-3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+8}{2*4}=\frac{-8}{8}
=-1
$